-(7x+3)=2x^2

Solution for -(7x+3)=2x^2 equation:

-(7x+3)=2x^2

We move all terms to the left:

-(7x+3)-(2x^2)=0

determiningTheFunctionDomain
-2x^2-(7x+3)=0

We get rid of parentheses

-2x^2-7x-3=0

a = -2; b = -7; c = -3;
Δ = b2-4ac
Δ = -72-4·(-2)·(-3)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-5}{2*-2}=\frac{2}{-4}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+5}{2*-2}=\frac{12}{-4}
=-3
$